By doing some quick interpolation and assuming there isn't some progressive or log function, something doesn't fit. If your two figures are correct, then whether done by interpolation or by using ratios, 110 newton meters per mm must equal roughly 630 pounds (between 628 and 635). No?
Damn your not only good looking but smart too.
Here is the chart I found in the Eibach Catalog.
The Physics and math will have to be explained by someone else.
Part number Length Dia. Force
mm in mm in n/mm lbs/in
0120.060.0050 120 4.75 60 2.36 50 285
0120.060.0060 120 4.75 60 2.36 60 342
0120.060.0070 120 4.75 60 2.36 70 400
0120.060.0080 120 4.75 60 2.36 80 457
0120.060.0090 120 4.75 60 2.36 90 514
0120.060.0100 120 4.75 60 2.36 100 571
0120.060.0120 120 4.75 60 2.36 120 685
0120.060.0140 120 4.75 60 2.36 140 799
0120.060.0160 120 4.75 60 2.36 160 913
0120.060.0180 120 4.75 60 2.36 180 1,027
0160.060.0080 160 6.30 60 2.36 80 457
0160.060.0090 160 6.30 60 2.36 90 514
0160.060.0100 160 6.30 60 2.36 100 571
0160.060.0120 160 6.30 60 2.36 120 685
0160.060.0140 160 6.30 60 2.36 140 799
0160.060.0160 160 6.30 60 2.36 160 913
0160.060.0180 160 6.30 60 2.36 180 1,027
0160.060.0200 160 6.30 60 2.36 200 1,142
0160.060.0220 160 6.30 60 2.36 220 1,256
0160.060.0240 160 6.30 60 2.36 240 1,370
0160.060.0260 160 6.30 60 2.36 260 1,484
0160.060.0280 160 6.30 60 2.36 280 1,598