I'm preparing to install the Blue Sea 6-circuit fuse block myself. Since the maximum rating of the fuse block is 100 amps. should I install a 100 amp relay?
USMC CWO, all you need is a 30 or 40 amp relay. You will need to fuse the hot lead from the battery with a 30amp fuse - this is the number you work with.
That is where I have the question. If I am running, say 4 accessories, each pulling 15 amps, will it blow the 30-amp main fuse?
If you're running 4 accessories each pulling 15 amps, your battery will be dead long before the fuse blows. That being said.....
I have two terminal blocks, one switched (Blue Sea) the other always hot.
Both of these are fed by the same 10awg 30 amp fused run from the battery.
I run from my blue sea -
CCS100 Cruise
Heated grips
Warm n Safe heated jacket
Gerbings heated pant liners and socks.
Fuel pump for aux tank.
From the always hot -
Soltek HID lights (fed to their own 30amp relay)
Two 15amp Powerlet sockets.
All through a 30 amp fuse with a 30 amp rated relay.
Keep in mind that the useage of the farkles varies - It would be very difficult to exceed 30 amps draw at any given time - do the math - 30 amps times 13.8 volts equals 414 watts - and the rated outputs of the bikes are 490 watts for the GenI, 590 watts for the GenII. (or therabouts)
Having 4 15amp circuits maxed out would draw 60amps x 13.8 volts equals 828 watts - meaning your battery would very rapidly become a doorstop.
Fuses are for protection to guard against shorts in your wiring or in the farkle itself. Go with the 30amp fuse on your feed from +12v battery, and you'll be fine.
I'm preparing to install the Blue Sea 6-circuit fuse block myself. Since the maximum rating of the fuse block is 100 amps. should I install a 100 amp relay?
USMC CWO, all you need is a 30 or 40 amp relay. You will need to fuse the hot lead from the battery with a 30amp fuse - this is the number you work with.
That is where I have the question. If I am running, say 4 accessories, each pulling 15 amps, will it blow the 30-amp main fuse?
Yep. Just add up the devices and that will be your total load. But I doubt you have 4 items each pulling 15 amps.
Formula for Power = I*E (current times voltage), so a 15 amp accessory at a nominal ~13V would consume 195 watts.
That's big power. 4 x 195 = 780 watts, way more power than the alternator is capable of pumping out.
Yep, what he said.