ionbeam
2 FUN
Test standards don't necessarily have to match a real world function. At 0ºF there are a number of things at play such as metal conduction going up and the chemical reactions slowing down. The SAE J537 Std. aims at a charge depletion(1) percentage and provides a fixed reference point around which many different curves can pass in determining CCA performance. There are other standards that can be used and one uses 8.4 volts as the reference voltage, but the standard being used has to be disclosed so the person seeing the report understands the differences.
When you work out the ionization (
) process for the chemical reactions, a lead/acid battery should have 2.04 volts per cell at a specific acid concentration, at a specific temperature, at a specific charge, at a specific rest period after charging. Then the curve ball is at open circuit, after all the other BS, the actual cell voltage will be ~2.1 volts. Battery voltage will rise 0.02 V for every 10ºF of temperature rise. 13.2 volts is usually an indication that the battery hasn't rested long enough to equalize before the voltage was read. With a calibrated meter
In the real world, 8.4 volts would be a pretty good cut-off voltage for starting. At this point the engine may not meet minimum cranking RPM because volts = cranking speed. The coil will be significantly weaker due to low voltage but it does have the advantage of a longer dwell time. At 8.4 volts and 100 cranking RPM the coil may still make a hot enough spark to ignite the fuel. At 8.4 volts at 5,000 RPM the coil may not be able to ignite the fuel and at 8,000 RPM at 8.4 volts -- well the engine probably won't be able to make 8,000 RPM.
(1) Not the battery depleted, just the available charge under load. A battery is >10% charged at 11.5 volts. You can find charts that show different %, I won't debate the actual state of charge, just take the point that a battery can be fully discharged by 11.0 volts.
Edit: I see Fred posted a similar thing while I was typing.
When you work out the ionization (
In the real world, 8.4 volts would be a pretty good cut-off voltage for starting. At this point the engine may not meet minimum cranking RPM because volts = cranking speed. The coil will be significantly weaker due to low voltage but it does have the advantage of a longer dwell time. At 8.4 volts and 100 cranking RPM the coil may still make a hot enough spark to ignite the fuel. At 8.4 volts at 5,000 RPM the coil may not be able to ignite the fuel and at 8,000 RPM at 8.4 volts -- well the engine probably won't be able to make 8,000 RPM.
(1) Not the battery depleted, just the available charge under load. A battery is >10% charged at 11.5 volts. You can find charts that show different %, I won't debate the actual state of charge, just take the point that a battery can be fully discharged by 11.0 volts.
Edit: I see Fred posted a similar thing while I was typing.
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