Woodstock
Well-known member
I'm not sure what you mean about the light sources illuminating things, but in the case of your example,Now we're getting to the meaty goodness. A little time gravy. So what you are saying then for this example, because the speed of light is the constant, then time has to bend, warp, dialate, whatever to compensate because we have said that C is constant.This is where it gets a little more interesting, because both time, and distance get measured differently. From the standpoint of 5 star base, your clock runs slower. Also, you measure distance (in the direction that you're traveling) as smaller (shorter). I can try and write something else up which gives a little bit more detail of the examples with some of the math, if you're interested.
In my first post in this topic, I muddied the water by mentioning the fact that the universe is expanding. Thanks to this discussion I'm now thinking of it differently. Instead of some boundry layer getting further from some center with the objects inside staying the same but just getting further apart from each other, the matter inside the universe is also expanding along with it, (at least the matter immediately surrounding my skeloton).
Still, I'm having trouble with the whole two bodies traveling away from each other thing. Isn't time relative to the observer? By that I mean whether I'm stationary or going 99.99999% C, when I do something like type on a keyboard I experience it the same. Only an outside observer would see me as typing very fast or very slow?
So if we have two bodies traveling away from each other at .6C from some center point:
A.6C<---------center----------->B.6C
Regardless of how observers experience time, after all they are traveling at the same velocity, would the observers still be able to see each other if:
1. they each have their own light source
2. they don't have their own light source and must be illuminated by some powerful spotlight on the other object thats powerfull enought to shine across the universe bla bla bla.
observers on A and B see each other moving away from each other at ~.882c
Assuming A moves at velocity a, and B moves at velocity b in the opposite direction, the combined velocity is:
( a + b ) / ( 1 + ( ( a * b ) / ( c^2 ) ) )
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